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22 February, 17:33

What is the ph of a solution with [oh-] = 2.6 * 10^-3 m?

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  1. 22 February, 20:29
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    POH = - log [ OH⁻]

    pOH = - log [ 2.6x10⁻³]

    pOH = 2.58

    pH + pOH = 14

    pH + 2.58 = 14

    pH = 14 - 2.58

    pH = 11.42
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