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6 November, 18:03

If the heat of combustion for a specific compound is - 1230.0 kJ/mol and its molar mass is 46.95 g/mol, how many grams of this compound must you burn to release 354.10 kJ of heat?

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  1. 6 November, 20:26
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    Moles of substance required = (energy required) / (energy per mole) = (-354.10) / (-1230.0) = 0.287886178 ... moles

    Mr = mass/moles so mass = Mr * moles = 46.95 * 0.28 ... = 13.5162561 = 13.5g (3sf)
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