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20 August, 01:26

A 25.0-milliliter sample of HNO3 (aq) is neutralized by 32.1 milliliters of 0.150 M KOH (aq). What is the molarity of the HNO3 (aq) ?

(1) 0.117 M (3) 0.193 M

(2) 0.150 M (4) 0.300 M

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  1. 20 August, 03:05
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    The answer is (3) 0.193M. To find the molarity of HNO3, you just need to use the M1V1=M2V2 equation (no need to worry about ionization constants because HNO3 is monoprotic and KOH dissociates 1:1). Since the molarity you are looking for is M1, you get M1=M2V2/V1 = (0.150) (32.1) / 25.0 = 0.193M
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