Write the isotope needed, by identifying A, Z, and X, to balance the following nuclear fission reaction: 23592U+10n→14056Ba+AZX+3 10n

The nuclear fission reaction is

²³⁵₉₂U + ¹₀n → ¹⁴⁰₅₆Ba + ᵃzX + 3 ¹₀ n

First we must balance all the protons:

92 + 0 = 56 + z + 3 (0)

z = 36

Next, we balance the nucleons (protons and neutrons)

235 + 1 = 140 + a + 3*1

a = 91

An atomic number of 36 is Krypton so, X is ⁹¹₃₆Kr.