Ask Question
23 May, 01:56

How many mL of 0.150M NaOH (base) solution are required to neutralize 35.0mL of 0.220M HCl (acid) solution?

+1
Answers (1)
  1. 23 May, 04:10
    0
    The neutralization reaction between an acid and a base is given through the equation,

    M₁V₁ = M₂V₂

    Substituting the known values from the given,

    (0.150 M) (V₁) = (35 mL) (0.220M)

    The value of V₁ from the equation above is 51.33 mL.

    Thus, 51.33 mL of NaOH is needed for the process.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How many mL of 0.150M NaOH (base) solution are required to neutralize 35.0mL of 0.220M HCl (acid) solution? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers