How many grams of sodium sulfide can be produced when 45.3 g Na react with 105 g S?

Unbalanced equation: Na + S → Na2S

Show, or explain, all of your work along with the final answer.

The chemical reaction would be as follows:

2Na + S → Na2S

We are given the amount of the reactants to be used in the reaction. We use these to calculate the amount of product. We do as follows:

45.3 g Na (1 mol / 22.99 g) = 1.97 mol Na

105 g S (1 mol / 32.06 g) = 3.28 mol S

The limiting reactant would be Na. We calculate as follows:

1.97 mol Na (1 mol Na2S / 2 mol Na) (78.04 g / mol) = 76.87 g Na2S produced