Titration of a 25.0 mL sample of barium hydroxide requires 34.45 mL of 0.100 M nitric acid. What is the molarity of the barium hydroxide?

The titration reaction is written as follows:

Ba (OH) 2 + 2HNO3 = Ba (NO3) 2 + 2H2O

The calculations are as done as follows:

0.100 mol HNO3 / L (.03445 L solution) = 0.003445 mol HNO3

0.003445 mol HNO3 (1 mol Ba (OH) 2 / 2 mol HNO3) = 0.001723 mol Ba (OH) 2

0.001723 mol / 0.025 L = 0.07 M Ba (OH) 2