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29 June, 21:04

What amount of heat is removed to lower the temperature of 80 grams of water from 75º C to 45º C? The specific heat of liquid water is 4.18 J/gº C.

A. - 10,000 J

B. 10,000 J

C. - 8,000 J

D. 8,000 J

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Answers (1)
  1. 29 June, 22:03
    0
    To be exact 9931.2 Joules to be removed from 80 grams of water.

    heat to be removed or added = Heat capacity * weight in grams * change in temperature

    the answer is B.
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