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22 July, 02:20

How many moles of gas will occupy a volume of 0.53 L at a temperature of 329 K and pressure of 3.0 atm? n = ... mol

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  1. 22 July, 04:42
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    You have to rewrite the ideal gas law in terms of n. (n=PV/RT)

    you are given V=0.53L, T=329K, and P=3.0atm, R is a constant so you already know that R=0.08206atmL/molK.

    n = (3.0atmx0.53L) / (0.08206atmL/molKx329K)

    n=0.0589mol gas
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