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Yesterday, 10:43

If 4.00 g of NaCl react with 10.00 g of AgNO3, what is the excess reactant?

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  1. Yesterday, 11:23
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    The reaction formula of this is NaCl + AgNO3 = NaNO3 + AgCl. The mole number of NaCl is 4/58.5=0.068 mol. The mole number of AgNO3 is 10/170=0.059 mol. So the NaCl is excess.
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