When 4.5 mol al react with 11.5 mol hcl, what is the limiting reactant, and how many moles of h2 can be formed?

Question

Chemistry

Pixie Stick

8 June, 10:32

When 4.5 mol al react with 11.5 mol hcl, what is the limiting reactant, and how many moles of h2 can be formed?

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Axel George · Answer 1

1° /. 2 Al + 6 HCl → 2 AlCl3 + 3 H2

k1 = n (Al) / 2 = 4,5 / 2 = 2,25

k2 = n (HCl) / 6 = 11,5 / 6 = 1,92

k2 HCl is the limiting reactant

6 mol of HCl - - - > 2 mol of H2

11,5 mol of HCl - - - > 3,83 mol of H2