Ask Question
26 March, 18:10

A student uses 3.00g of a fertilizer with an npk ratio of 15-15-10, how much mgnh4po4*6h2o (mm = 245.1 g/mol) should the student produced?

+3
Answers (1)
  1. 26 March, 21:24
    0
    Supposing all of the P in the fertilizer is converted PO4 anions in the Mg salt:

    (3.00 g) x (0.15) / (30.97376 g P/mol) x (1 mol MgNH4PO4*6H2O / 1 mol P) x (245.1 g MgNH4PO4*6H2O/mol) =

    3.56 g MgNH4PO4*6H2O
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A student uses 3.00g of a fertilizer with an npk ratio of 15-15-10, how much mgnh4po4*6h2o (mm = 245.1 g/mol) should the student produced? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers