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29 January, 15:47

If 40.0 g of HCl react with an excess of magnesium metal, what is the theoretical yield of hydrogen?

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  1. 29 January, 16:58
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    Balanced equation: Mg+2HCl=MgCl2 + H2

    Showing that if Mg is not a limiting factor then 2 moles of HCl on complete reaction liberate 1 mole of Hydrogen

    therefore:

    1 mole of HCl=35.5g, 40g=x

    X = 40/35.5 = 1.127mole

    2 moles of HCl = 1 moles of Hydrogen

    1.127=X

    X=1.127/2 = 0.56

    the theoretical yield of hydrogen
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