In the formula XBr3, the symbol x could represent the element, A. Al B. Mg C. H or D. S

Well, by looking at the periodic table and determining the ionic charge or combining capacity for these individual options, we can see that A. Aluminum is the only one that will form a cation, after donating a total of 3 electrons to that of Bromine, resulting in the compound of AlBr3. Al has a charge of + 3 after giving its 3 valence electrons to Bromine.