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3 December, 19:11

How much ko2 is needed to react with 75.0 l of carbon dioxide at - 25˚c and 215 kpa?

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  1. 3 December, 22:56
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    First, we convert the pressure in kPa to atm. That is,

    (215 kPa) x (1 atm / 101.325 kPa) = 2.122 atm

    Then, determine the amount of carbon (C) in mol by assuming that it is an ideal gas.

    n = (2.122 atm) (75 L) / (0.0821 L. atm/mol. K) (-25 + 273.15)

    n = 7.81 mols

    The reaction is expressed as,

    4KO2 + 2CO2 - - > 2K2CO3 + 3O2

    From the equation,

    (7.81 mols CO2) x (4 mols KO2/2 mols CO2) = 15.62 mols KO2
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