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13 August, 16:45

If there is initially 1.334 m o2, how long will it take for the o2 concentration to reach 0.443 m?

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  1. 13 August, 16:51
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    To answer, we take it that the rate of the consumption of O2 in this item is directly proportional to its concentration in first degree such that,

    -dCa/dt = kCa

    Solving,

    -dCa/Ca = kt

    lnCa - lnCao = - kt

    Substituting,

    ln (0.443) - ln (1.334) = - k (t)

    t = 1.1023/k
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