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11 September, 15:42

A 75.0g sample of liquid contains 17.5% by mass of H3PO4 (molar mass = 98.0g/mol). If

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  1. 11 September, 18:28
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    Assuming no other acid is in the H3PO4 mix, then

    a) the equation

    2H3PO4 + 3Ba (OH) 2>>3H2O+Ba3 (PO3) 2

    titration equation:

    nb*Ma*Va=na*Mb*Vb

    nb*molesacid=na*molesbase

    3*75*.175/98=2*Molaritybase*.215

    0.927 mol/L
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