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28 March, 03:41

A rubber ball contains 5.70*10⁻¹ dm³ of gas at a pressure of 1.05 atm. What volume will the gas occupy at 7.47 atm?

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  1. 28 March, 06:08
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    Assuming ideal gas behavior:

    P1V1 = P2V2

    V2 = P1V1/P2 = 1.05 atm * 0.570 liters / 7.47 atm = 0.080 liters
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