Ask Question
27 June, 14:42

The reaction between hydrogen and oxygen to yield water vapor has ΔH∘=-484kJ: 2H2 (g) + O2 (g) →2H2O (g) ΔH∘=-484kJ

How much PV work is done in kilojoules for the reaction of 3.20 mol of H2 with 1.60 mol of O2 at atmospheric pressure if the volume change is - 22.6L?

Express your answer using three significant figures

+5
Answers (1)
  1. 27 June, 17:46
    0
    The work done * on * a system that undergoes an infinitesimal volume change, dV under the influence of an * external * pressure of p is given by:

    δw = - p dV

    If p is constant, this integrates to:

    w = - p*ΔV

    In this case,

    w = - (101325 Pa) * (-7.3 L) (1m3/1000L) = 2289.945 J
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The reaction between hydrogen and oxygen to yield water vapor has ΔH∘=-484kJ: 2H2 (g) + O2 (g) →2H2O (g) ΔH∘=-484kJ How much PV work is ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers