How much Sr (OH) 2 • 8 H2O (M = 265.76) is needed to prepare 250.0 ML of solution in which [OH] = 0.100M?

Question

Chemistry

Ryker

5 August, 01:00

How much Sr (OH) 2 • 8 H2O (M = 265.76) is needed to prepare 250.0 ML of solution in which [OH] = 0.100M?

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Answers (1)

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Jacob Meadows · Answer 1

Use the formula

first step:

Use the formula

molarity = mole/liter

change ml to l

plug in data

to get. 1=mole/.25 or. 1M*.25liter

which =.025 moles

then divide. 025 moles by two because there are two OH in Sr (OH) 2

then multiply that by 265.76 (the molar mass of water)

.0125*265.76

which is 3.32grams this is your answer