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11 March, 10:58

How many grams of NH3 are needed to provide the same number of molecules as in 0.75 g of SF6

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  1. 11 March, 14:26
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    0.75g SF6 x (1 mol SF6 / 146.1g SF6) x (1 mol NH3 / 1 mole SFg) x (17.03g NH3 / mol NH3) = 0.087g NH3
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