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10 May, 23:58

What is the molarity of a solution that contains 85.0 grams of Na2SO4 in 325 milliliters of solution? (The mass of one mole of Na2SO4 is 142 grams.)

0.195 M

0.599 M

1.84 M

6.22 M

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  1. 11 May, 03:32
    0
    First find the number of mol

    85/142 = 0.598 mol

    divide the mol by the volume in L

    0.598/0.325 = 1.81M. C is close enough
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