What volume of 14.7 M acetic acid (HC2H3O2) contains 9.7g of acetic acid?

First, we convert grams to moles using molar mass. Then we can use stoichiometry to convert moles to liters using the knowledge that M equals moles over liters.

So, to solve:

Step 1: 9.7 g acetic acid x (1 mole acetic acid/60.05g acetic acid) x (1 L/14.7 moles acetic acid) = 0.011 L acetic acid