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31 March, 13:26

What volume of a 6.67 m nacl solution contains 3.12 mol nacl?

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  1. 31 March, 13:59
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    The volume of a 6.67 m nacl solution that contains 3.12 mol nacl is 0.468.

    You just need to follow this formula:

    C = n / V

    So, it will be

    V = n / C

    = 3.12 / 6.67 moles / Liter

    = 0.468 L
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