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28 November, 10:33

What volume of oxygen gas, in milliliters, is required to react with 0.640 g of SO2 gas at STP?

11.2 mL

22.4 mL

112 mL

224 m

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Answers (1)
  1. 28 November, 11:44
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    SO2 + O2 - - - > SO3. Moles of SO2 = 0.64/32+16X2 = 0.01mole. According to stoichiometry, moles of SO2 = moles of O2 = 0.01mol. Therefore volume of oxygen gas at STP = 22.4 x moles of O2 = 22.4 x 0.01 = 0.224 = 224mL.
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