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28 September, 21:07

Given the following chemical equation, if 58 grams of aluminum reacts with excess chlorine gas and was found to produce 203 grams of aluminum chloride, what is the percent yield for this reaction?2Al + 3 Cl2 - - > 2AlCl3

35%

24%

71%

68%

+2
Answers (1)
  1. 29 September, 00:27
    0
    1st find mol of Al = 58/27 = 2.148 mol

    There is a 1:1 ratio between AlCl3 and Al so 2.148 mol should be produced

    take 2.148 * 133.5 = 286.75 g should be produced

    % yield = 203/286.75 =.707 = 71% or C
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