Given 2.91 moles of a gas in a 500 milliliter-container, if the temperature is found to be 31 degrees Celsius, what is the pressure of the gas? (The ideal gas constant is 0.0821 L · atm/mol · K.)

1.45 x 102 atm

1.48 x 101 atm

1.45 x 10-1 atm

1.45 x 101 atm

Question

Dallas Webb

26 May, 07:28

+2

Answers (1)

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Shania Andersen · Answer 1

Use the PV = nRT equation T is in Kelvins = 31 + 273 = 304 K

P (0.5) = (2.91) (0.0821) (304)

P (0.5) = 72.6289

P = 145.25 atm or 1.45x10^2 atm

Given 2.91 moles of a gas in a 500 milliliter-container, if the temperature is found to be 31 degrees Celsius, what is the pressure of the gas? (The ideal gas constant is 0.0821 L · atm/mol · K.)1.45 x 102 atm1.48 x 101 atm1.45 x 10-1 atm1.45 x 101 atm