How many moles are equal to 28 grams of CaCO3

Question

Chemistry

Sheldon Crosby

17 July, 17:43

How many moles are equal to 28 grams of CaCO3

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Answers (1)

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Karter Choi · Answer 1

N (CaCO3) = m:M

m being the mass of the sample and M being the molar mass of the compound; Molar mass is to be obtained by adding the atomic masses of all the elements in the compound.

therefore,

n (CaCO3) = m:M

=28g:100 g. mol

=0.28 mol

therefore, there are 0.28 moles in 28g of Calcium Carbonate.