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10 January, 21:53

You have a series of four chemical reactions (1->2->3->4). How do you calculate the triangleH2 if you know the other triangleH values?

A. Triangle H2 = triangleH1 + triangleH3 - triangleH4

B. Triangle H2 = triangleH1 + triangleH3 + triangleH4

C. Triangle H2 = triangleH4 - (triangleH1 + triangleH3)

D. Triangle H2 = (triangleH1) (triangleH3) (triangleH4)

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  1. 10 January, 23:21
    0
    Given:

    Δ H1 → Δ H2 → Δ H3 → Δ H4

    Answer would be:

    C. Triangle H2 = Triangle H4 - (Triangle H1 + Triangle H3)

    Your basis would be triangle H4. If you're looking for triangle H4, simply add triangles H1 to H3.
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