Ask Question
15 May, 11:54

How do you determine a limiting or excess reagent

+2
Answers (1)
  1. 15 May, 12:14
    0
    Determine the mol ratio of both the reagents

    Then calculate the mol for both reagents

    eg NaOH + HCl - - > NaCl + H2O

    given in qns NaOH is 5g and 50cm^3 of 0.2mol/dm^3 HCL

    from eqn:

    Mole ratio of NaOH to HCL = 1:1

    from calculations:

    no. of mole of NaOH = 5 / (23+16 + 1) = 0.125mol (excess)

    no. of mole of HCL = 0.2 * 50/1000 = 0.01 mol (limiting)

    NaOH : HCL should equals to 1:1 however from calculations it is not 1:1 and n (HCL) < n (NaOH) HCL limiting, NaOH excess
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How do you determine a limiting or excess reagent ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers