What is the limiting reactant when 8.4 moles of lithium react with 4.6 moles of oxygen gas?

Unbalanced equation: Li + O2 → Li2O

Show, or explain, all of your work along with the final answer.

First balance the equation

4Li + O2 - > 2Li2O

then to figure the limiting reactant use the numbers in front of each reactant as a ratio

4:2 for Li to Li2O

1:2 for O2 to Li2O

then use those to multiple or divide the number if moles to get the moles of Li2O it would make

Li=8.4 and because it's 4:2 (or 2:1) then 1 mole of Li make half as many moles of Li2O.

8.4/2 = 4.2

O2 = 4.6 and the ratio is 1:2 meaning 1 mole of O2 makes twice as many moles of Li2O

4.6x2 = 9.2