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22 August, 10:28

An aqueous solution is 26.0% by mass ammonia, nh3, and has a density of 0.904 g/ml. what is the molality of ammonia?

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  1. 22 August, 12:29
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    V=1cm³

    ms = 0,904g * 0,26 = 0,23504g

    M=17,04g/mol

    n = m / M = 0,23504g / 17,04g/mol ≈ 0,0138mol

    mso = 0,904g - 0,23504g = 0,66896g

    C = 0,0138mol / 0,66896g = 0,021 mol/0,001kg=21 mol/kg
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