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19 August, 17:12

Determine the density of nh3 gas at 435k and 1.00atm

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  1. 19 August, 17:29
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    We assume that this gas is ideal. Therefore, we can use the ideal gas equation which is expressed as:

    PV=nRT

    We manipulate this equation to give us an expression which will correspond to density. We do as follows:

    PV = nRT

    P/RT = n/V where n = m/MM

    P (MM) / RT = m/V = density

    Density = 1.00 (17.03) / 0.08206 (435)

    Density = 0.48 g / L
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