Ask Question
9 December, 04:16

The rate constant for the first order decomposition of A at 500oC is 9.2 x 10-3 s-1. how long will it take for 90.8% of a 0.500 M sample of A to decompose? Question options:

+1
Answers (1)
  1. 9 December, 07:29
    0
    For this problem, we assume a first-order kinetics which has a kinetics expression written as:

    ln (Ca/Cao) = - kt

    We use this formula to solve for time, t. First we list the needed values,

    k = 9.2 x 10-3 s-1

    Cao = 0.500 M

    Xa = 90.8% = 1 - (Ca/Cao)

    Ca = 0.046 M

    ln (0.046/0.500) = - 9.2 x 10-3 s-1 (t)

    t = 259.34 s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The rate constant for the first order decomposition of A at 500oC is 9.2 x 10-3 s-1. how long will it take for 90.8% of a 0.500 M sample of ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers