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15 June, 21:58

MnO2 + 4HCl reacts to form MnCl2 + CL2 + 2H2O If. 86 mol of MnO2 and 48.2 g of HCl react, which reactant is the limiting reagent

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  1. 15 June, 22:12
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    HCl:

    m=48,2g

    M=36,5g/mol

    n = m/M = 48,2g / 36,5g/mol = 1,32mol

    1mol : 4mol

    MnO ₂ + 4HCl ⇒ MnCl₂ + Cl₂ + 2H₂O

    0,86mol : 1,32mol

    limiting reagent

    0,33 will react

    HCl is limiting reagent.
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