MnO2 + 4HCl reacts to form MnCl2 + CL2 + 2H2O If. 86 mol of MnO2 and 48.2 g of HCl react, which reactant is the limiting reagent

Question

Chemistry

Mckenzie Webster

15 June, 21:58

MnO2 + 4HCl reacts to form MnCl2 + CL2 + 2H2O If. 86 mol of MnO2 and 48.2 g of HCl react, which reactant is the limiting reagent

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Answers (1)

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Alexus Bruce · Answer 1

HCl:

m=48,2g

M=36,5g/mol

n = m/M = 48,2g / 36,5g/mol = 1,32mol

1mol : 4mol

MnO ₂ + 4HCl ⇒ MnCl₂ + Cl₂ + 2H₂O

0,86mol : 1,32mol

limiting reagent

0,33 will react

HCl is limiting reagent.