What volume of 0.6 m hcl is required to neutralize 100.0 ml of 0.5 m naoh?

In order to determine the amount needed, we have to know the chemical reaction that would happen between the substances. In this case the reaction would be:

NaOH + HCl = NaCl + H2O

We calculate as follows:

.1 L (0.5 mol NaOH / L) (1 mol HCl / 1 mol NaOH) (1 L / 0.6 mol HCl) = 0.08 L or 80 mL of 06 M HCl

Hope this answers the question. Have a nice day.