What is the molality of glycerol solution with density og 1.120g/ml and mass percentage of 48%?

Molality = moles of solute per a kilogram of solvent.

In 100 grams of solution we can say we have 48 grams of solute and 52 grams of solvent.

Convert the 48 grams of Glycerol to moles of Glycerol by dividing it by it's molar mass. The result would be approx. 0.52.

0.52 mol Glycerol / 52 gr solvent = 0.01 molal