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25 June, 21:54

At 1 atm, how much energy is required to heat 39.0 g of h2o (s at - 24.0 °c to h2o (g at 121.0 °c?

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  1. 25 June, 22:18
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    Q = mcΔt, q = energy [J] m = mass (of water) [g]; c = specific heat capacity of water [J g⁻¹ K⁻¹/°C⁻¹]; Δt = change in temperature [K/°C]

    Δt = 121 - - 24 = 145

    q = 39 * 4.18 * 145

    q = 23637.9 J
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