When 26.62 miles of FeS2 reacts with 5.44 miles of O2 how many miles of SO2 are formed

4 parts of FeS2 reacts with 11 parts of O2

so 26,62 moles of FeS2 would need 26,62/4 * 11 = 73,2 moles of O2

So only 5,44 / 11 * 4 = 1,98 moles of FeS2 reacts with 5,44 moles of O2, O2 is the limiting

reactant

This means FeS2 is the reactant in excess and 26,62 - 5,44 = 21,18 moles of FeS2 are left over

and 1,98 * 8/4 = 3,96 moles of SO2 are formed