A buffer solution contains. 120 M acetic acid and. 150 M sodium acetatea. how many moles of acetic acid and of sodium acetate are present in 50.0 mL of solution?

How many moles of acetic acid and of sodium acetate are present in 50.0 mL of solution?

We calculate it as follows:

moles of acetic acid =.120 mol/L (.050 L) = 0.006 mol

moles of sodium acetate = 0.150 mol/L (0.050 L) = 0.008 mol

Hope this answers the question. Have a nice day.