Calculate the vapor pressure of a solution made by dissolving 109 grams of glucose (molar mass = 180.2 g/mol in 920.0 ml of water at 25 °c. the vapor pressure of pure water at 25 °c is 23.76 mm hg. assume the density of the solution is 1.00 g/ml.

Given dа ta: molar mass = 180.2 g/mol in 920.0 ml of water at 25 °c.

the vapor pressure of pure water at 25 °c is 23.76 mm hg.

Asked: the vapor pressure of a solution made by dissolving 109 grams of glucose

Solution:

moles glucose = 109 g / 180.2 g/mol=0.605

mass water = 920 mL x 1 g/mL = 920 g

moles water = 920 g / 18.02 g/mol=51.1

mole fraction water = 51.1 / 51.1 + 0.605 = 0.988

vapor pressure solution = 0.988 x 23.76 = 23.47 mm Hg