Ask Question
11 February, 09:56

How do you prepare a 250 ml of a 2.35 m hf dilution from a 15.0 m stock solution

+5
Answers (1)
  1. 11 February, 13:18
    0
    In dilution problems involving known concentrations and volumes of the solution, a widely used equation is:

    C1V1 = C2V2

    Where:

    C1 = Concentration of Solution 1

    V1 = Volume of Solution 1

    C2 = Concentration of Solution 2

    V2 = Volume of Solution 2

    Substituting the given values gives: (2.35 M) * (250mL) = (15.0 M) * V2

    V2 = 39.17 mL

    So, you must initially have 39.17 mL of 15 M solution and dilute it to 250 mL to achieve a 2.35 M solution
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How do you prepare a 250 ml of a 2.35 m hf dilution from a 15.0 m stock solution ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers