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7 July, 10:29

Molar solubility of CuBr Ksp = 6.3 x 10-9

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  1. 7 July, 13:14
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    First, lets write the equation: CuBr--> Cu+2 + Br-

    then, write the Ksp expression: Ksp = [Cu+2] [Br-] = 6.3 x 10-9

    We let x be the concentration of Ksp that dissolved. Ksp = (x) (x) = 6.3 x 10-9.

    Now we solve for x

    X^2 = 6.3x10-9

    x = square root (6.3x10-9)

    x = 7.94x10-5
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