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10 September, 06:06

In the reaction K2CrO4 (aq) + PbCl2 (aq) → 2KCl (aq) + PbCrO4 (s), how many grams of PbCrO4 will precipitate out from the reaction between 500.0 milliliters of 3.0 M K2CrO4 in an excess of PbCl2?

A. 1.5 grams

B. 3.0 grams

C. 480 grams

D, 150 grams

I don't understand how i would find the answer.

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Answers (1)
  1. 10 September, 07:48
    0
    This is a stoichiometry question. but the answer is not listed.

    500.0 ml (1 Liter / 1000 mL) (3.0 moles / 1 L) (1 mole PbCrO4 / 1 mole K2CrO40) (194 grams / 1 mole K2CrO4) = 291 grams of K2CrO4 produced.
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