In the reaction K2CrO4 (aq) + PbCl2 (aq) → 2KCl (aq) + PbCrO4 (s), how many grams of PbCrO4 will precipitate out from the reaction between 500.0 milliliters of 3.0 M K2CrO4 in an excess of PbCl2?
A. 1.5 grams
B. 3.0 grams
C. 480 grams
D, 150 grams
I don't understand how i would find the answer.
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