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15 November, 20:10

What is the change in temperature in a 128g sample of titanium if it absorbs 2808J of heat energy at a temperature of 2°C? The specific heat of titanium is 0.523J / g °c.

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  1. 15 November, 22:34
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    Given:

    128g sample of titanium

    2808J of heat energy

    specific heat of titanium is 0.523 J / g °C.

    Required:

    Change in temperature

    Solution:

    This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.

    Plugging in the values into the equation

    H = mCpT

    2808J = (128g) (0.523 J / g °C) T

    T = 41.9 °C
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