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27 October, 01:02

What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K?

0.715 kPa

2.45 kPa

28.2 kPa

62.7 kPa

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  1. 27 October, 02:28
    0
    PV=nRT (where R = 0.082057)

    P (35.5) = 0.540*0.082057*223

    P=0.2783 atm convert to kPa

    P=28.2kPa
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