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11 April, 08:51

When you add 0.295 g of sodium metal to an excess of hydrochloric acid, you find that 3070 j of heat are produced. what is the enthalpy of the reaction as written below?

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  1. 11 April, 11:33
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    Since the following can have this reaction:

    2Na (s) + 2 HCl (aq) → 2NaCl (aq) + H2 (g)

    0.295 g Na = 0.295 / 23 = 0.0128 mol

    0.0128 mol - - - > 3070 J, so 2 mol Na - - - > 3070 j / 0.0156 mol x 2 mol = 393589.74 j
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