What is the pressure of the ideal gas when the volume is decreased to 4.0 L and the temperature is increased to 265 K?

Pressure = 2.0atm

volume = 5.0L

temp. = 215 K

It is an ideal gas therefore we can use the ideal gas equation to solve the problem. The ideal gas equation is expressed as PV = nRT. First, we solve the amount of the gas in moles using the said equation and the first conditions.

(2.0 atm) (5.0 x 10^3 cm^3) = n (82.0575 atm. cm^3/mol. K) (215 K)

n=0.5668 mol

Using the second conditions given, we obtain the new pressure.

P (4.0 x 10^3) = 0.5668 x 82.0575 x 265

P = 3.08 atm