35.0 mL of acid with an unknown concentration is titrated with 24.6 mL of 0.432 M base. What is the concentration of the acid? Assume the acid contributes 1 mole of (H+) ions/mole of acid and the base contributes 1 mole of (OH-) ions/mole of base.

3.29 M

0.615 M

0.304 M

Question

Chemistry

Sosa

17 December, 21:59

35.0 mL of acid with an unknown concentration is titrated with 24.6 mL of 0.432 M base. What is the concentration of the acid? Assume the acid contributes 1 mole of (H+) ions/mole of acid and the base contributes 1 mole of (OH-) ions/mole of base.

3.29 M

0.615 M

0.304 M

+5

Answers (1)

Know the Answer?

Maddison Irwin · Answer 1

Given:

35.0 mL of acid with an unknown concentration

24.6 mL of 0.432 M base

Required:

Concentration of the acid

Solution:

M1V1 = M2V2

M1 (35.0 mL of acid) = (0.432 M base) (24.6 mL of base)

V1 = (0.432 M base) (24.6 mL of base) / (35.0 mL of acid)

M1 = 0.304 M of acid

35.0 mL of acid with an unknown concentration is titrated with 24.6 mL of 0.432 M base. What is the concentration of the acid? Assume the acid contributes 1 mole of (H+) ions/mole of acid and the base contributes 1 mole of (OH-) ions/mole of base.3.29 M0.615 M0.304 M

35.0 mL of acid with an unknown concentration is titrated with 24.6 mL of 0.432 M base. What is the concentration of the acid? Assume the acid contributes 1 mole of (H+) ions/mole of acid and the base contributes 1 mole of (OH-) ions/mole of base.

3.29 M

0.615 M

0.304 M