Calculate Delta E when 33.0 g of carbon dioxide sublimes at 77.0 K and 1 ATM

To solve this problem, we establish the general energy balance:

ΔE = ΔU + ΔKE + ΔPE

ΔE = Q + W

Q + W = ΔU + ΔKE + ΔPE

In this case, ΔKE and ΔPE are both zero or negligible.

Given:

m = 33.0 grams of CO2

Tsub = 77 K

P = 1 atm

ΔE = Q + W

ΔE = mCpΔT + ΔPV

solve for mCpΔT, find the value of Cp for CO2, then solve for Q. Next, solve for W using the ideal gas law. Add the two values and that will be the value of the delta E.